0=(27x^3-8)/(3x-2)

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Solution for 0=(27x^3-8)/(3x-2) equation: 


D( x )

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x in (-oo:2/3) U (2/3:+oo)

0 = (27*x^3-8)/(3*x-2) // - (27*x^3-8)/(3*x-2)

0-((27*x^3-8)/(3*x-2)) = 0

-((27*x^3-8)/(3*x-2)) = 0

(-1*(27*x^3-8))/(3*x-2) = 0

( -1 )

-1 = 0

x belongs to the empty set

( 27*x^3-8 )

27*x^3 = 8 // : 27

x^3 = 8/27

x^3 = 8/27 // ^ 1/3

x = 2/3

x in { 2/3} 

x belongs to the empty set

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